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AP Physics 1: 2.3 System Interactions and Changes 193 Views


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AP Physics 1: System Interactions and Changes Drill 2, Problem 3. What is the acceleration of the box?

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Transcript

00:00

Thank you We sneak and here's your shmoop du jour

00:05

Brought to you by static friction Some materials have a

00:08

low coefficient of friction And with other materials like say

00:12

us in our bed almost no amount of force can

00:15

make a move All right twenty kilogram boxes dropped onto

00:18

his surface with a static friction coefficient of zero point

00:21

five in a kinetic friction coefficient of zero point two

00:24

a force of eighty newtons is applied to the box

00:28

What is the acceleration of the box And here the

00:32

potential answers in meters per second squared All right well

00:35

we here at shmoop love information We crave it but

00:39

there is such a thing as too much information For

00:42

example one time we told a friend that we still

00:44

sleepin batman pajamas And that was definitely a t m

00:47

i And this question wealth a little tricky because it

00:50

has too much information also but let's tackle the math

00:53

First first thing we have to do is get this

00:55

box moving And to do that we need to overcome

00:58

the force of static friction Well to calculate that force

01:01

we just multiply the normal force in this case mass

01:04

Times Gravity by the coefficient of friction so here's the

01:07

equation Once we have the numbers we need we plug

01:11

him in and find that the force of friction is

01:13

one hundred newtons Since the force acting on the box

01:17

is only eighty new queens the box is going nowhere

01:20

fast so the correct answer is just option a zero

01:22

meters per second squared and sense is not gonna budge

01:26

The kinetic friction coefficient doesn't matter No movement equals no

01:30

kinetic friction That's What we mean by t m i

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