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College Tour: New York University 13 Views


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Description:

If you're looking for a big school experience at one of the highest-ranked national universities, NYU might be your cup of tea. Then again, if you're really into cups of tea, Oxford might be more your style.

Language:
English Language

Transcript

00:04

And here's your Shmoop du jour, brought to you by spectators. [Man juggling balls on stage]

00:08

Because what’s the point of doing something cool if nobody’s watching?

00:12

Here’s today’s question.

00:14

In the neutralization reaction between CH3 CO OH and Na OH, which of the following ions

00:20

are spectator ions?

00:26

And here are our potential answers.

00:28

Well, just like the spectators at a sporting event, spectator ions are key components. [Spectators watching a sporting game]

00:33

And just like the spectators at a sporting event, spectator ions don’t get to participate. [Ions on a football field]

00:38

When we write out a chemical reaction, spectator ions will appear on both sides, unchanged.

00:43

We need to examine this neutralization reaction in more detail so we can figure out who the

00:47

spectators are.

00:49

Unfortunately, these ones don’t identify themselves with foam fingers and face paint. [Spectator ions scribbled out]

00:54

The first thing we need to do is identify the stronger acid or base.

00:58

This species will dissociate completely and allow the neutralization reaction to proceed. [Acid and base stood side by side]

01:03

You probably don’t recognize acetic acid, CH3 CO OH, as an especially strong acid,

01:11

but hopefully you do recognize sodium hydroxide, NA OH, as a strong base. [NaOH dancing in a club]

01:16

If not, it’d probably be a good idea to review your list of strong bases.

01:22

Anyway, sodium hydroxide will completely dissociate in water, producing Na+ and OH-

01:28

ions.

01:29

The OH- will take a proton from the acid, CH3 CO OH, and the overall reaction will yield [OH- taking a proton from an acid]

01:36

water and sodium acetate, as a salt.

01:39

This salt will dissociate in water. [Salt poured into a beaker]

01:41

Get all that?

01:42

Now let’s write this reaction in terms of ions for those species that dissociate.

01:47

So who are the spectators?

01:48

Well, we can identify spectators based on their lack of participation in this reaction.

01:53

The only ion that appears on both sides of the reaction, unchanged, is the sodium ion, [Sodium ions in reaction circled]

01:58

Na+, making our answer D. Now that was well worth watching, wasn’t

02:02

it?

02:03

What can we say?

02:04

We here at Shmoop like to put on a show. [People dancing in a street talent show]

02:05

…we just hope someone will come watch our tap routine next time.

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