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AP Calculus BC Videos 14 videos

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AP Calculus 2.3 Limits 208 Views


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Description:

AP Calculus 2.3 Limits. Which of the following facts is helpful in determining the limit?


Transcript

00:00

Thank you We sneak here's your smoke too Sure brought

00:05

to you by sine x If you're having signed x

00:09

problems we recommend suiting All right which of the following

00:15

facts is helpful in determining the limit of sine x

00:18

over acts as x approaches npr All right And here

00:23

the potential answers This is it Okay so we've got

00:28

one of those choose the right roman numerals questions In

00:34

this case we're trying to see which one of these

00:36

facts helps us determine the limit Ok so let's go

00:39

through each option and pick out the ones that are

00:41

true Roman numeral one negative one over acts is less

00:45

than or equal to sign of acts over x is

00:48

also less than or equal to one over x Well

00:52

when we deal with trying to find limits have founded

00:54

trig functions like this we know instantly it's a job

00:58

for the squeezing serum dresses It works much better with

01:01

functions that goes with it squeezing terms as if the

01:04

output of a function f of acts is always between

01:07

the outputs of two other functions g of axe and

01:10

h of x and g of axe and h of

01:13

x both approached the lind l as x approaches infinity

01:17

then the function half of acts also obstruct his scalp

01:21

as x approaches infinity Okay so we know from the

01:25

basic during function graph sign of acts that the y

01:27

values of sine x are limited betweennegative one and one

01:30

in other words sign effects is unfounded So if we

01:34

just divide the entire inequality by Acts we'd get negative

01:37

1 over acts It is less than or equal to

01:40

sign x over x which is last center equal to

01:42

one over x This will definitely help us find the

01:46

limit The boom roman numeral one is correct and we

01:49

can cross off answers Be seeing me because well they

01:51

include one group Now we just have to check to

01:54

see if roman numeral two is correct Since there's no

01:57

answer Choice with options One two three All being through

02:00

the next step in applying squeezing term is to actually

02:03

find the limits His ex approaches infinity of each of

02:05

the parts of the inequality The negative one over accident

02:08

signed x over act and the one over act which

02:12

means we just have to know the limit of one

02:14

overnegative acts and won over axes X approaches infinity For

02:18

that we have statement too statement to tells us that

02:21

the limit of one over axes x approaches is zero

02:24

Perfect Of course we still need to know the limit

02:27

of negative one over access x approaches infinity to solve

02:30

the limit as x approaches Infinity of sine x overact

02:34

bye Statements one into both Tell during the limit Statement 00:02:39.23 --> [endTime] from him to our true Our answers Yeah

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